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98=6x^2+7x
We move all terms to the left:
98-(6x^2+7x)=0
We get rid of parentheses
-6x^2-7x+98=0
a = -6; b = -7; c = +98;
Δ = b2-4ac
Δ = -72-4·(-6)·98
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-49}{2*-6}=\frac{-42}{-12} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+49}{2*-6}=\frac{56}{-12} =-4+2/3 $
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